1. Using Dr. Guinn's figures from his own laboratory tests, let us try to group Mannlicher-Carcano bullet fragments.
2. We will use 5 actual fragments from 2 bullets - 2 from bullet 6002 and 3 from bullet 6003. Top figure for each bullet s antimony content, bottom figure is silver content.
|
358 983 | 667 395 363
____ ____ | ____ ____ ____
9.1 10.3 | 15.9 9.6 8.3
|
6002 A 6002 A1 | 6003 A1 6003 A2 6003 A3
|
Situation A Situation B Situation C
| |
363 358 | 983 358 | 983 667 395
____ ____ | ____ ____ | ____ ____ ____
8.3 9.1 | 10.3 9.1 | 10.3 15.9 9.6
| |
6003 A2 6002 A | 6002 A1 6002A | 6002 A1 6003 A 6003 A1
| |
3. In Situation A, would Guinn not have made the interpretation that these were two fragments from the same bullet? THEY ARE ACTUALLY TWO FRAGMENTS FROM TWO DIFFERENT BULLETS.
4. In Situation B, would Guinn not have made the interpretation that he had found 2 fragments from two different bullets? IN FACT, BOTH FRAGMENTS ARE FROM ONE BULLET.
5. In Situation C, how many bullets probably produced the 3 fragments? Guinn's findings would probably have pointed to 3 separate bullets. IN FACT, THE THREE FRAGMENTS ARE FROM TWO BULLETS. Ironically, if Guinn chose to go to his second most important element, silver, in this analysis, this would have led him to link the two fragments which had silver contents Of 9.6 and 10.3, the wrong combination!
B>